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28-y^2=7y
We move all terms to the left:
28-y^2-(7y)=0
We add all the numbers together, and all the variables
-1y^2-7y+28=0
a = -1; b = -7; c = +28;
Δ = b2-4ac
Δ = -72-4·(-1)·28
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{161}}{2*-1}=\frac{7-\sqrt{161}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{161}}{2*-1}=\frac{7+\sqrt{161}}{-2} $
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